Ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old the younger one, find their present age?

Let the present age of one person be=x
Let the present age of second person be=x+16
6 Years ago age of elder person=x+16-6=x+10
Age of the younger person=x-6
According to the given statement:
x+10=3(x-6)
x+10=3x-18
10+18=3x-x
2x=28
x=28/2
x=14
Younger Age=14
Elder Age=14+16=30