- “__” is a binary operation on N
- “/” is not a binary operation on N
- “+” is a binary operation on N
- “x” is a binary operation on N
- a
-
Addition, Subtraction, Multiplication and Division are examples of Binary Operations.
Mathematics MCQs
All Mathematical MCQs from different papers are solved in this sections. All Math related MCQs have uploaded in this portion of ETEST Website. Visitors should visit ETEST Website regularly for Best Jobs Tests Preparation because ETEST Team updates ETEST Website on daily basis.
Anwar has six times as much money as Meera. If Anwar gives Rs.80 to Meera, both of them will have equal amounts of money. At the beginning Meera has money ____
- 32
- 62
- 82
- 192
- a
The value of (1-Cos2x) X (1+Cot2x)=_____
- 1
- 2
- 4
- a
If d > 0 and 5d2-45=0, what is the value of d?
- -3
- -9,+9
- -3,+3
- +3
- d
What is the average of first 150 natural numbers?
- 50
- 55.5
- 68.5
- 75.5
- d
The average of the set of the numbers is 65,85,70,90 and 105 is _____
- 80
- 83
- 85
- 87
- b
-
Sum of Numbers=65+85+70+90+105=415
Total Numbers=5
Average=Sum of Numbers / Total Numbers
Average=415/5=83
The average age of 3 boys is 15 years and their ages are in proportions 3:5:7. The age in year of the younger boys is:
- 08
- 09
- 10
- 11
- a
-
Suppose,
Age of 3 Boys=3x+5x and 7z
According to Questions:
(3x+5x+7y)/3=15
15x/3=15
15x=15*3
15x=45
x=45/15
x=3
According to Question, the age of younger boys=3x
3x=3(3)=9
Two members are in the ratio 3:4. If the sum of numbers is 63, the members are ____
- 30,33
- 23,40
- 55,12
- 27,36
- d
-
Sum of Two Ratios=3+4=7
Sum of Numbers=63
First Number=3/7*63=27
Second Number=4/7*63=36
Therefore, two numbers are 27 and 36.
If 16 men do a job in 20 days, then 32 men can do the same job in _____ days.
- 05
- 10
- 15
- 20
- b
-
16 men can do a job in 20 days
Total Work=16*20=320
Let 32 men do same job in X days
32x=320
x=320/32
x=10
Ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old the younger one, find their present age?
- 16,32
- 18,34
- 12,28
- 14,30
- d
-
Let the present age of one person be=x
Let the present age of second person be=x+16
6 Years ago age of elder person=x+16-6=x+10
Age of the younger person=x-6
According to the given statement:
x+10=3(x-6)
x+10=3x-18
10+18=3x-x
2x=28
x=28/2
x=14
Younger Age=14
Elder Age=14+16=30